def create_labels()

in frauddetector/frauddetector.py [0:0]
20 lines of code
6 McCabe index (conditional complexity)

    def create_labels(self, labels):
        """Create Amazon FraudDetector labels.  Wraps the boto3 SDK API to allow bulk operations.
        https://docs.aws.amazon.com/frauddetector/latest/ug/create-a-label.html
        https://boto3.amazonaws.com/v1/documentation/api/latest/reference/services/frauddetector.html#FraudDetector.Client.put_label

        Args:
            :labels: (list)    List object containing labels to instantiate with associated Amazon Fraud Detector
                                        [
                                            {
                                                "name": "legit"
                                            },
                                            {
                                                "name": "fraud"
                                            }
                                        ]
        Returns:
            :response_all:              {variable_name: API-response-status, variable_name: API-response-status} dict
        """

        existing_names = [l['name'] for l in self.labels['labels']]
        response_all = []

        for l in labels:
            if l['name'] not in existing_names:
                # create label via Boto3 SDK fd instance
                lh.debug("put_label: {}".format(l['name']))
                response = self.fd.put_label(
                    name=l['name'],
                    description=l['name']
                )
                lh.info("create_labels: label {} created".format(l['name']))
                status = {l['name']: response['ResponseMetadata']['HTTPStatusCode']}
                response_all.append(status)
            else:
                lh.warning("create_labels: label {} already exists, skipping".format(l['name']))
                status = {l['name']: "skipped"}
                response_all.append(status)

        # update myself
        self.variables = self.fd.get_labels()

        # convert list of dicts to single dict
        response_all = {k: v for d in response_all for k, v in d.items()}
        return response_all