def __get_policy_by_name()

in scripts/create_update_scps.py [0:0]

• 6 lines of code
• 4 McCabe index (conditional complexity)

def __get_policy_by_name(_paginator, scp_name):
    for page in _paginator.paginate(Filter='SERVICE_CONTROL_POLICY'):
        for __scp in page["Policies"]:
            if __scp["Name"] == scp_name:
                return __scp
    return None