func()

in s2/rect.go [367:428]
47 lines of code
16 McCabe index (conditional complexity)

func (r Rect) IntersectsCell(c Cell) bool {
	// First we eliminate the cases where one region completely contains the
	// other. Once these are disposed of, then the regions will intersect
	// if and only if their boundaries intersect.
	if r.IsEmpty() {
		return false
	}
	if r.ContainsPoint(Point{c.id.rawPoint()}) {
		return true
	}
	if c.ContainsPoint(PointFromLatLng(r.Center())) {
		return true
	}

	// Quick rejection test (not required for correctness).
	if !r.Intersects(c.RectBound()) {
		return false
	}

	// Precompute the cell vertices as points and latitude-longitudes. We also
	// check whether the Cell contains any corner of the rectangle, or
	// vice-versa, since the edge-crossing tests only check the edge interiors.
	vertices := [4]Point{}
	latlngs := [4]LatLng{}

	for i := range vertices {
		vertices[i] = c.Vertex(i)
		latlngs[i] = LatLngFromPoint(vertices[i])
		if r.ContainsLatLng(latlngs[i]) {
			return true
		}
		if c.ContainsPoint(PointFromLatLng(r.Vertex(i))) {
			return true
		}
	}

	// Now check whether the boundaries intersect. Unfortunately, a
	// latitude-longitude rectangle does not have straight edges: two edges
	// are curved, and at least one of them is concave.
	for i := range vertices {
		edgeLng := s1.IntervalFromEndpoints(latlngs[i].Lng.Radians(), latlngs[(i+1)&3].Lng.Radians())
		if !r.Lng.Intersects(edgeLng) {
			continue
		}

		a := vertices[i]
		b := vertices[(i+1)&3]
		if edgeLng.Contains(r.Lng.Lo) && intersectsLngEdge(a, b, r.Lat, s1.Angle(r.Lng.Lo)) {
			return true
		}
		if edgeLng.Contains(r.Lng.Hi) && intersectsLngEdge(a, b, r.Lat, s1.Angle(r.Lng.Hi)) {
			return true
		}
		if intersectsLatEdge(a, b, s1.Angle(r.Lat.Lo), r.Lng) {
			return true
		}
		if intersectsLatEdge(a, b, s1.Angle(r.Lat.Hi), r.Lng) {
			return true
		}
	}
	return false
}