1 00:00:00,000 --> 00:00:02,667 (air whooshing) 2 00:00:05,310 --> 00:00:06,420 - In this video, 3 00:00:06,420 --> 00:00:09,881 we will study together 'the Unigram Language Model 4 00:00:09,881 --> 00:00:13,288 subword tokenization algorithm'. 5 00:00:13,288 --> 00:00:15,567 The overall training strategy 6 00:00:15,567 --> 00:00:18,450 of a Unigram Language Model tokenizer 7 00:00:18,450 --> 00:00:21,480 is to start with a very large vocabulary 8 00:00:21,480 --> 00:00:24,240 and then to remove tokens at each iteration 9 00:00:24,240 --> 00:00:27,300 until we reach the desired size. 10 00:00:27,300 --> 00:00:28,530 At each iteration, 11 00:00:28,530 --> 00:00:30,930 we will calculate a loss on our training corpus 12 00:00:30,930 --> 00:00:33,480 thanks to the Unigram model. 13 00:00:33,480 --> 00:00:37,470 As the loss calculation depends on the available vocabulary, 14 00:00:37,470 --> 00:00:40,563 we can use it to choose how to reduce the vocabulary. 15 00:00:41,550 --> 00:00:43,620 So we look at the evolution of the loss 16 00:00:43,620 --> 00:00:47,103 by removing in turn each token from the vocabulary. 17 00:00:48,000 --> 00:00:50,430 We will choose to remove the p-percents 18 00:00:50,430 --> 00:00:52,200 which increase the loss the less. 19 00:00:56,310 --> 00:00:57,540 Before going further 20 00:00:57,540 --> 00:01:00,240 in the explanation of the training algorithm, 21 00:01:00,240 --> 00:01:02,973 I need to explain what is an Unigram model. 22 00:01:04,183 --> 00:01:06,030 The Unigram Language Model 23 00:01:06,030 --> 00:01:08,493 is a type of Statistical Language Modem. 24 00:01:09,450 --> 00:01:10,980 A Statistical Language Model 25 00:01:10,980 --> 00:01:13,530 will assign a probability to a text 26 00:01:13,530 --> 00:01:18,090 considering that the text is in fact a sequence of tokens. 27 00:01:18,090 --> 00:01:21,090 The simplest sequences of tokens to imagine 28 00:01:21,090 --> 00:01:24,753 are the words that compose the sentence or the characters. 29 00:01:26,130 --> 00:01:28,890 The particularity of Unigram Language Model 30 00:01:28,890 --> 00:01:32,010 is that it assumes that the occurrence of each word 31 00:01:32,010 --> 00:01:34,533 is independent of its previous word. 32 00:01:35,400 --> 00:01:37,620 This assumption allows us to write 33 00:01:37,620 --> 00:01:39,570 that the probability of a text 34 00:01:39,570 --> 00:01:42,210 is equal to the product of the probabilities 35 00:01:42,210 --> 00:01:43,953 of the tokens that compose it. 36 00:01:45,840 --> 00:01:50,220 It should be noted here that it is a very simple model 37 00:01:50,220 --> 00:01:53,850 which would not be adapted to the generation of text 38 00:01:53,850 --> 00:01:57,840 since this model would always generate the same token, 39 00:01:57,840 --> 00:02:00,453 the one which has the greatest probability. 40 00:02:01,320 --> 00:02:03,360 Nevertheless, to do tokenization, 41 00:02:03,360 --> 00:02:05,790 this model is very useful to us 42 00:02:05,790 --> 00:02:07,440 because it can be used 43 00:02:07,440 --> 00:02:10,893 to estimate the relative likelihood of different phrases. 44 00:02:14,100 --> 00:02:15,000 We are now ready 45 00:02:15,000 --> 00:02:19,830 to return to our explanation of the training algorithm. 46 00:02:19,830 --> 00:02:21,690 Let's say that we have as a training corpus 47 00:02:21,690 --> 00:02:23,880 with 10 times the word hug, 48 00:02:23,880 --> 00:02:25,410 12 times the word pug, 49 00:02:25,410 --> 00:02:27,330 5 times the word lug, 50 00:02:27,330 --> 00:02:28,560 4 times bug 51 00:02:28,560 --> 00:02:29,943 and 5 times dug. 52 00:02:33,120 --> 00:02:34,560 As said earlier, 53 00:02:34,560 --> 00:02:37,473 the training starts with a big vocabulary. 54 00:02:38,460 --> 00:02:41,400 Obviously, as we are using a toy corpus, 55 00:02:41,400 --> 00:02:44,430 this vocabulary will not be that big 56 00:02:44,430 --> 00:02:46,773 but it should show you the principle. 57 00:02:47,610 --> 00:02:51,870 A first method is to list all the possible strict substrings 58 00:02:51,870 --> 00:02:53,823 and that's what we'll do here. 59 00:02:54,780 --> 00:02:58,170 We could also have used the BPE algorithm 60 00:02:58,170 --> 00:03:00,010 with a very large vocabulary size 61 00:03:01,410 --> 00:03:05,103 but for now, the strict substrings are enough. 62 00:03:06,990 --> 00:03:09,120 The training of the Unigram tokenizer 63 00:03:09,120 --> 00:03:12,093 is based on the Expectation-Maximization method. 64 00:03:13,320 --> 00:03:15,120 At each iteration, 65 00:03:15,120 --> 00:03:17,430 we estimate the probabilities of the tokens 66 00:03:17,430 --> 00:03:18,430 of the vocabulary 67 00:03:20,130 --> 00:03:23,100 and then we remove the p-percent of tokens 68 00:03:23,100 --> 00:03:26,070 that minimize the loss on the corpus 69 00:03:26,070 --> 00:03:28,900 and which do not belong to the basic character 70 00:03:29,880 --> 00:03:33,150 as we want to keep in our final vocabulary 71 00:03:33,150 --> 00:03:36,693 the basic characters to be able to tokenize any word. 72 00:03:37,770 --> 00:03:39,641 Let's go for it! 73 00:03:39,641 --> 00:03:42,360 The probability of a token simply estimated 74 00:03:42,360 --> 00:03:44,760 by the number of appearance of this token 75 00:03:44,760 --> 00:03:46,440 in our training corpus 76 00:03:46,440 --> 00:03:50,133 divided by the total number of appearance of all the tokens. 77 00:03:51,510 --> 00:03:54,390 We could use this vocabulary to tokenize our words 78 00:03:54,390 --> 00:03:56,283 according to the Unigram model. 79 00:03:57,150 --> 00:04:00,892 We will do it together to understand two things: 80 00:04:00,892 --> 00:04:04,110 how we tokenize a word with a Unigram model 81 00:04:04,110 --> 00:04:07,803 and how the loss is calculated on our corpus. 82 00:04:09,088 --> 00:04:12,263 The Unigram LM tokenization of our text 'Hug' 83 00:04:12,263 --> 00:04:15,270 will be the one with the highest probability of occurrence 84 00:04:15,270 --> 00:04:17,403 according to our Unigram model. 85 00:04:19,080 --> 00:04:21,750 To find it, the simplest way to proceed 86 00:04:21,750 --> 00:04:24,120 would be to list all the possible segmentations 87 00:04:24,120 --> 00:04:25,800 of our text 'Hug', 88 00:04:25,800 --> 00:04:29,340 calculate the probability of each of these segmentations 89 00:04:29,340 --> 00:04:32,043 and then choose the one with the highest probability. 90 00:04:33,210 --> 00:04:34,920 With the current vocabulary, 91 00:04:34,920 --> 00:04:38,640 two tokenizations get exactly the same probability. 92 00:04:38,640 --> 00:04:40,080 So we choose one of them 93 00:04:40,080 --> 00:04:42,603 and keep in memory the associated probability. 94 00:04:43,710 --> 00:04:46,380 To compute the loss on our training corpus, 95 00:04:46,380 --> 00:04:48,570 we need to tokenize as we just did 96 00:04:48,570 --> 00:04:50,673 all the remaining words in the corpus. 97 00:04:52,290 --> 00:04:56,430 The loss is then the sum over all the words in the corpus 98 00:04:56,430 --> 00:04:58,920 of the frequency of occurrence of the word 99 00:04:58,920 --> 00:05:02,670 multiplied by the opposite of the log of the probability 100 00:05:02,670 --> 00:05:05,463 associated with the tokenization of the word. 101 00:05:07,620 --> 00:05:10,803 We obtain here a loss of 170. 102 00:05:13,830 --> 00:05:18,630 Remember, our initial goal was to reduce the vocabulary. 103 00:05:18,630 --> 00:05:21,870 To do this, we will remove a token from the vocabulary 104 00:05:21,870 --> 00:05:24,213 and calculate the associated loss. 105 00:05:27,630 --> 00:05:30,627 Let's remove for example, the token 'ug'. 106 00:05:31,920 --> 00:05:35,370 We notice that the tokenization for 'hug' 107 00:05:35,370 --> 00:05:39,990 with the letter 'h' and the tuple 'ug' is now impossible. 108 00:05:39,990 --> 00:05:42,240 Nevertheless, as we saw earlier 109 00:05:42,240 --> 00:05:45,180 that two tokenizations had the same probability, 110 00:05:45,180 --> 00:05:47,730 we can still choose the remaining tokenization 111 00:05:47,730 --> 00:05:51,093 with a probability of 1.10e-2. 112 00:05:52,410 --> 00:05:55,350 The tokenizations of the other words of the vocabulary 113 00:05:55,350 --> 00:05:57,060 also remain unchanged. 114 00:05:57,060 --> 00:06:00,600 And finally, even if we remove the token 'ug' 115 00:06:00,600 --> 00:06:05,403 from our vocabulary the loss remains equal to 170. 116 00:06:06,630 --> 00:06:08,100 For this first iteration, 117 00:06:08,100 --> 00:06:10,080 if we continue the calculation, 118 00:06:10,080 --> 00:06:13,050 we would notice that we could remove any token 119 00:06:13,050 --> 00:06:16,110 without it impacting the loss. 120 00:06:16,110 --> 00:06:19,200 We will therefore choose at random to remove the token 'ug' 121 00:06:19,200 --> 00:06:21,843 before starting a second iteration. 122 00:06:24,240 --> 00:06:27,300 So we estimate again the probability of each token 123 00:06:27,300 --> 00:06:30,630 before calculating the impact of each token on the loss. 124 00:06:32,160 --> 00:06:33,990 For example, if we remove now 125 00:06:33,990 --> 00:06:36,290 the token composed of the letters 'h' and 'u', 126 00:06:37,350 --> 00:06:41,013 there is only one possible tokenization left for hug. 127 00:06:41,940 --> 00:06:44,700 The tokenization of the other words of the vocabulary 128 00:06:44,700 --> 00:06:45,633 is not changed. 129 00:06:46,560 --> 00:06:47,393 In the end, 130 00:06:47,393 --> 00:06:49,200 we obtain by removing the token 131 00:06:49,200 --> 00:06:52,749 composed of the letters 'h' and 'u' from the vocabulary, 132 00:06:52,749 --> 00:06:56,430 a loss of 168. 133 00:06:56,430 --> 00:06:59,490 Finally, to choose which token to remove, 134 00:06:59,490 --> 00:07:02,490 we will for each remaining token of the vocabulary, 135 00:07:02,490 --> 00:07:04,800 which is not an elementary token, 136 00:07:04,800 --> 00:07:07,380 calculate the associated loss. 137 00:07:07,380 --> 00:07:09,843 Then, compare these losses between them. 138 00:07:11,730 --> 00:07:13,800 The token which we will remove 139 00:07:13,800 --> 00:07:17,340 is the token which impacts the least the loss, 140 00:07:17,340 --> 00:07:18,870 here the token 'bu'. 141 00:07:20,040 --> 00:07:22,380 We had mentioned at the beginning of the video 142 00:07:22,380 --> 00:07:24,930 that at each iteration we could remove 143 00:07:24,930 --> 00:07:27,093 p-percent of the tokens by iteration. 144 00:07:29,356 --> 00:07:33,000 The second token that could be removed at this iteration 145 00:07:33,000 --> 00:07:34,317 is the token 'du'. 146 00:07:36,510 --> 00:07:37,920 And that's it. 147 00:07:37,920 --> 00:07:39,720 We just have to repeat these steps 148 00:07:39,720 --> 00:07:43,203 until we get the vocabulary of the desired size. 149 00:07:45,030 --> 00:07:46,500 One last thing. 150 00:07:46,500 --> 00:07:50,310 In practice, when we tokenize a word with a Unigram model, 151 00:07:50,310 --> 00:07:53,130 we don't compute the set of probabilities of 152 00:07:53,130 --> 00:07:55,500 all the possible splits of a word 153 00:07:55,500 --> 00:07:58,770 before comparing them to keep the best one 154 00:07:58,770 --> 00:08:01,440 but we use the Viterbi algorithm 155 00:08:01,440 --> 00:08:04,563 which is much more efficient way to do it. 156 00:08:06,540 --> 00:08:07,680 And that's it! 157 00:08:07,680 --> 00:08:09,270 I hope that this example 158 00:08:09,270 --> 00:08:10,987 has allowed you to better understand 159 00:08:10,987 --> 00:08:12,933 the Unigram tokenization algorithm. 160 00:08:14,355 --> 00:08:17,022 (air whooshing)