var executeCommand = function()

in gulpfile.js [104:113]


var executeCommand = function(cmd, callback) {
    shell.exec(cmd, {silent: true}, function(code, output) {
       if(code != 0) {
           console.error("command failed: " + cmd + "\nManually execute to debug");
       }
       else {
           callback();
       }
    });
}