_splitCJKName()

in name_utils.js [165:213]

• 27 lines of code
• 6 McCabe index (conditional complexity)

  _splitCJKName(nameTokens) {
    // The convention for CJK languages is to put the surname (last name) first,
    // and the given name (first name) second. In a continuous text, there is
    // normally no space between the two parts of the name. When entering their
    // name into a field, though, some people add a space to disambiguate. CJK
    // names (almost) never have a middle name.

    let reHangulName = new RegExp(
      "^[" + this.HANGUL_RANGE.join("") + this.WHITESPACE.join("") + "]+$");
    let nameParts = {
      given: "",
      middle: "",
      family: "",
    };

    if (nameTokens.length == 1) {
      // There is no space between the surname and given name. Try to infer
      // where to separate between the two. Most Chinese and Korean surnames
      // have only one character, but there are a few that have 2. If the name
      // does not start with a surname from a known list, default to one
      // character.
      let name = nameTokens[0];
      let isKorean = reHangulName.test(name);
      let surnameLength = 0;

      // 4-character Korean names are more likely to be 2/2 than 1/3, so use
      // the full list of Korean 2-char surnames. (instead of only the common
      // ones)
      let multiCharSurnames = (isKorean && name.length > 3) ?
        this.KOREAN_MULTI_CHAR_SURNAMES :
        this.COMMON_CJK_MULTI_CHAR_SURNAMES;

      // Default to 1 character if the surname is not in the list.
      surnameLength =
        multiCharSurnames.some(surname => name.startsWith(surname)) ? 2 : 1;

      nameParts.family = name.substr(0, surnameLength);
      nameParts.given = name.substr(surnameLength);
    } else if (nameTokens.length == 2) {
      // The user entered a space between the two name parts. This makes our job
      // easier. Family name first, given name second.
      nameParts.family = nameTokens[0];
      nameParts.given = nameTokens[1];
    } else {
      return null;
    }

    return nameParts;
  },