joinNameParts()

in name_utils.js [274:279]

• 6 lines of code
• 4 McCabe index (conditional complexity)

  joinNameParts({given, middle, family}) {
    if (this._isCJKName(given) && this._isCJKName(family) && middle == "") {
      return family + given;
    }
    return [given, middle, family].filter(part => part.length).join(" ");
  },