def filename()

in mozdownload/scraper.py [0:0]

• 9 lines of code
• 3 McCabe index (conditional complexity)

    def filename(self):
        """File name of the downloaded file."""
        if os.path.splitext(self.destination)[1]:
            # If the filename has been given make use of it
            target_file = self.destination
        else:
            # Otherwise determine it from the url.
            parsed_url = urlparse(self.url)
            source_filename = (parsed_url.path.rpartition('/')[-1] or
                               parsed_url.hostname)
            target_file = os.path.join(self.destination, source_filename)

        return os.path.abspath(target_file)